# Thread: Answer plzzzz

1. ## Answer plzzzz

REMOVE RADICAL SIGN!
1/underroot 8

plz explain the way u adopt as I know nothing about it
****!THANKS 4 SPENDING YOUR PRECIOUS TIME!***

2. Originally Posted by Peacewanters007
REMOVE RADICAL SIGN!
1/underroot 8

plz explain the way u adopt as I know nothing about it
****!THANKS 4 SPENDING YOUR PRECIOUS TIME!***
Hello,

I assume that you know: $\sqrt{a} \cdot \sqrt{a} = a$ and

$\sqrt{a \cdot b} = \sqrt{a} \cdot \sqrt{b}$ . Then:

$\frac1{\sqrt{8}}=\frac1{\sqrt{8}} \cdot \frac{\sqrt{8}}{\sqrt{8}}= \frac{\sqrt{8}}{8} = \frac{\sqrt{4} \cdot \sqrt{2}}{8}=\frac{\not 2^1 \cdot \sqrt{2}}{\not 8_4}=\frac{\sqrt{2}}{4}$