# Thread: I should know this but it is frusterating me: story problem

1. ## I should know this but it is frusterating me: story problem

I dont know what it is with me and story problems but i can never seem to figure them out no matter how long i try.

so for your help i will be eternally grateful.

How many pounds of hamburger worth $1.05 per pound must be mixed with 60 pounds of hamburger worth$0.90 per poundto produce hamburger worth$1.00 per pound? 2. Originally Posted by Audriella I dont know what it is with me and story problems but i can never seem to figure them out no matter how long i try. so for your help i will be eternally grateful. How many pounds of hamburger worth$1.05 per pound must be mixed with 60 pounds of hamburger worth $0.90 per poundto produce hamburger worth$1.00 per pound?
Let $\displaystyle x$ be the pounds of missing hamburger!

$\displaystyle 1.05x+.9*60=(60+x)*1$

$\displaystyle 1.05x+54=60+x$

$\displaystyle 0.05x=6$

$\displaystyle x=120$ pounds

3. Thanks
and i know i should have known that
but thank you.

4. Colby is correct, but just to explain what happened here:

Let $\displaystyle x$ be the amount we require

Then at the end we will have $\displaystyle x + 60$ pounds of hamburger. We want this to cost $1 per pound. So the cost will be$\displaystyle 1(x + 60) = x + 60$Now the cost of the 60-pound hamburger is:$\displaystyle 60(0.90) = 54$And the cost of burger$\displaystyle x$is:$\displaystyle 1.05x$We want the total cost to be the same as$\displaystyle x + 60$, hence we have:$\displaystyle 54 + 1.05x = x + 60$Now solve for$\displaystyle x\$, and you will get Colby's answer