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Thread: please tell me

  1. #1
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    please tell me

    plz tell me a clear difference b\w rational irrrational and polynomial plzzz with examples
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  2. #2
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    Quote Originally Posted by Peacewanters007 View Post
    plz tell me a clear difference b\w rational irrrational and polynomial plzzz with examples
    Rational numbers can be represented by a/b, where a and b are integers.
    $\displaystyle \frac{2}{3}, \frac{99}{1170} $ are examples. If you write it in decimal form, it is either terminating, e.g. 1/2=0.5 or non-terminating but repeating, e.g. 1/3=0.333333....

    IRRational numbers, when represented in decimal form is non-terminating and non-repeating. It cannot be represented as a/b for any integers a,b. Examples are $\displaystyle \sqrt{2}, 5\sqrt{3}, \pi$

    Polynomials are of the form $\displaystyle a_{0}+a_{1}x^{1}+...+a_{n}x^{n}$ where x are variables or indeterminates and $\displaystyle a_{i}s $ are real numbers and x are natural numbers. For example, $\displaystyle 3x^{3} + 2x +7$. Here, $\displaystyle a_{0}=7, a_{1}=2, a_{2}=0, a_{3}=3$.
    NOte that the exponents of x should be natural numbers for it to be a polynomial
    Last edited by wiz_girl; Jan 4th 2008 at 07:09 AM.
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  3. #3
    GAMMA Mathematics
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    Quote Originally Posted by Peacewanters007 View Post
    plz tell me a clear difference b\w rational irrrational and polynomial plzzz with examples
    A polynomial is an algebraic equation such as: $\displaystyle ax^2+bx+c$

    Rational numbers can be expressed as a fraction of integers: $\displaystyle \frac{a}{b}$

    Irrational numbers cannot be expressed as a fraction of integers such as: $\displaystyle \pi$ or $\displaystyle e$
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by wiz_girl View Post
    Rational numbers can be represented by a/b, where a and b are integers.
    Quote Originally Posted by colby2152 View Post
    Rational numbers can be expressed as a fraction of integers: $\displaystyle \frac{a}{b}$
    for $\displaystyle b \ne 0$ of course.

    great explanation guys
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  5. #5
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    Quote Originally Posted by Jhevon View Post
    for $\displaystyle b \ne 0$ of course.

    great explanation guys
    yeah, right... sorry
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