x^3+6x^2-11x+8divided by x+1
please solve completely
THANKS
Hi Peacewanters007!
The remainder when $\displaystyle P(x)$ is divided by $\displaystyle x-a$ is $\displaystyle P(a)$.
So the remainder when $\displaystyle x^3+6x^2-11x+8$ is divided by $\displaystyle x+1$ is:
$\displaystyle P(-1) = (-1)^3+6(-1)^2-11(-1)+8 = -1+6+11+8=\boxed{24}$