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Math Help - Worded problem

  1. #1
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    Worded problem

    Hey everyone,

    Sorry to annoy you again with another eally easy question but i can't seem to be able to get the right answer. Here's the question:

    Three girls are playing scrabble. At the end of the game, the total of their scores adds up to 504. Annie scored 10% more than Belinda, while Cassie scored 60% of the combined scores of the other two. What did each player score?

    Thanks in advance for the help.
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  2. #2
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    let A be Annie's score, B be Belinda's score and C be Cassies score.

    At the end of the game, the total of their scores adds up to 504
    so A+B+C = 504

    Annie scored 10% more than Belinda
    A = B+B*10/100

    while Cassie scored 60% of the combined scores of the other two
    C = 10/100*(A+B)

    I think you can probably continue from here.
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  3. #3
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    Thanks for that. I think I should be alright now
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  4. #4
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    Wait, why does C=10/100*(A+B)

    Why 10%?
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  5. #5
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Stevo_Evo_22 View Post
    Wait, why does C=10/100*(A+B)

    Why 10%?
    It should be C = 60/100*(A + B). It was probably a typo.

    -Dan
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  6. #6
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    Thanks I thought so, but wasn't quite sure.

    Thanks for the help!
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  7. #7
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    Ok so the equation is:

    A*10/100 + 60/100*(A+B) + B = 504 ?

    If so, I still can't get the answer
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  8. #8
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Stevo_Evo_22 View Post
    Ok so the equation is:

    A*10/100 + 60/100*(A+B) + B = 504 ?

    If so, I still can't get the answer
    try to get everything in one variable. from the second equation given, solve for B to get it in terms of A. in the (corrected) third equation, plug in that formula for B to get C in terms of A. then plug all those formulas into the first equation A + B + C = 504. the last equation should have only A's in it, in which case it will be easy to solve
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  9. #9
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    How do i solve it for B?
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  10. #10
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Stevo_Evo_22 View Post
    How do i solve it for B?
    A = B + \frac 1{10}B ...........add the B's

    \Rightarrow A = \frac {11}{10}B .........multiply both sides by 10/11

    \Rightarrow B = \frac {10}{11}A
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  11. #11
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    Thanks heaps-I got the answers.

    Just one question-How do you know what to put it in terms of? For example how did you know to get it in terms of A?
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  12. #12
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Stevo_Evo_22 View Post
    Thanks heaps-I got the answers.

    Just one question-How do you know what to put it in terms of? For example how did you know to get it in terms of A?
    no particular reason, i just felt like it. you could have solved for B also. putting everything in terms of C might have been a problem
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