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Math Help - Angles of Triangle

  1. #1
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    Angles of Triangle

    In the figure, Angle DAB=20 degrees and AB = AD = CD. Find the value of x and y. x being angle ADB, y being angle BDC.

    All help is appreciated. DCB is 20 degrees right?
    Last edited by Rocher; December 21st 2007 at 08:40 PM.
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  2. #2
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    You need to attach the figure or we cannot tell what DCB is.

    Since AB = AD, \triangle ABD is isosceles so the base angles are the same.

    Also, the angles of a triangle add up to 180^o

    Now see if you can continue.
    Last edited by badgerigar; December 22nd 2007 at 12:53 AM. Reason: Forgot math tags
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  3. #3
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    Hello, Rocher!

    We still need more specifics.
    Do we have a parallelogram?


    In the figure: . \angle DAB = 20^o,\;AB = AD = CD
    Find: . x = \angle ADB,\:y =  \angle BDC.
    According to your description, CD can be anywhere . . .
    Code:
                                  D
                                  *
                              *  x *    *
                          *         *   y     *
                      *              *              *
                  *                   *                  * C
              *  20                   *
          *  *  *  *  *  *  *  *  *  *  *
          A                             B
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  4. #4
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    Here is the figure:

    Nevermind.
    Attached Thumbnails Attached Thumbnails Angles of Triangle-stupid-math-2.bmp  
    Last edited by Rocher; December 22nd 2007 at 08:50 AM.
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  5. #5
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    Quote Originally Posted by Rocher View Post
    In the figure, Angle DAB=20 degrees and AB = AD = CD. Find the value of x and y. x being angle ADB, y being angle BDC.

    All help is appreciated. DCB is 20 degrees right?
    This diagram is messed up somehow. Every statement you made above has something wrong with it!

    Angle x is ABD, not ADB. Angle y is CAD, not BDC. You have AB = AD = AC, not AB = AD = CD. DCB is a straight line segment, not an angle. And though this is not a critical point to make, angle DAB doesn't look anywhere near 20 degrees on your diagram.

    -Dan
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  6. #6
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    Heh, I'm a retard. Drew the wrong figure, and now its time for class. Oh well, thanks guys.
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