How do you simplify: (7+15i)-(14-i) How do you find the reciprocal of: (-6-7i)/(-3+5i)
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$\displaystyle \frac{1}{{a + bi}} = \frac{{a - bi}}{{a^2 + b^2 }}$
Originally Posted by Plato $\displaystyle \frac{1}{{a + bi}} = \frac{{a - bi}}{{a^2 + b^2 }}$ What is that supposed to mean to me regarding imaginary numbers?
Originally Posted by agentlopez How do you find the reciprocal of: (-6-7i)/(-3+5i) The reciprocal of any fraction a/b is b/a. (So long as a is not 0.) So the reciprocal of $\displaystyle \frac{-6 - 7i}{-3 + 5i}$ is $\displaystyle \frac{-3 + 5i}{-6 - 7i}$ Now you need to rationalize this expression. This is what Plato's comment refers to. -Dan
Originally Posted by agentlopez What is that supposed to mean to me regarding imaginary numbers? Perhaps you have misunderstood the purpose of a site such as this one. We offer help with problems; we generally do not give instruction. You asked for help with reciprocals of complex numbers. That is exactly what I gave you.
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