I need help with few probs very fast plz help!! 1) 2) 3) 4) 5) 6)
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heres the first one
For the second one solve the first part for y to get y = 2x-10 and then sub that into the second equation to get: x + 3(2x-10) = -9, now solve for x and then sub back in to either of the given equations and solve for y also.
9b^2c + 6c ----------- ......3c Is the same as: 9b^2c + 6c ------ ----- ...3c.......3c or 3b^2 + 2 does that make sense?
notice that 27 is 3*(3^2) notice that 12 is 3*(2^2)
Originally Posted by mathelp I need help with few probs very fast plz help!! ... 5) 6) Hello, to Nr. 5: to 6.: Greetings EB
Thnaks bro so much
can you show me 2,4 how to do?
#4 Graph both equations on a graphing calculator and the point where they intersect is your answer of the form (x,y)
Here is the graphs,
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