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Thread: phys quiz question please help me, thank you

  1. #1
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    Talking phys quiz question please help me, thank you

    The quantity of heat Q that changes the temperature T of a mass m of a substance is given by Q = mcT, where c is the specific heat capacity of the substance. For example, for H20, c = 1 cal/g°C. And for a change of phase the quantity of heat Q that changes the phase of a mass m is Q = mL, where L is the heat of fusion or heat of vaporization of the substance. For example, for H20 the heat of fusion is 80 cal/g or 80 kcal/kg, and the heat of vaporization is 540 cal/g or 540 kcal/kg. Use these relationships to determine the number of calories to change
    (a) 0.6 kg of 0°C ice to 0.6 kg 0°C ice water
    kcal
    (b) 0.6 kg of 0°C ice water to 0.6 kg 100°C boiling water
    kcal
    (c) 0.6 kg of 100°C boiling water to 0.6 kg l00°C steam
    kcal
    (d) 0.6 kg of 0°C ice to 0.6 kg 100°C steam
    kcal
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  2. #2
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    Quote Originally Posted by johnjohn View Post
    The quantity of heat Q that changes the temperature T of a mass m of a substance is given by Q = mcT, where c is the specific heat capacity of the substance. For example, for H20, c = 1 cal/g°C. And for a change of phase the quantity of heat Q that changes the phase of a mass m is Q = mL, where L is the heat of fusion or heat of vaporization of the substance. For example, for H20 the heat of fusion is 80 cal/g or 80 kcal/kg, and the heat of vaporization is 540 cal/g or 540 kcal/kg. Use these relationships to determine the number of calories to change
    (a) 0.6 kg of 0°C ice to 0.6 kg 0°C ice water
    kcal
    (b) 0.6 kg of 0°C ice water to 0.6 kg 100°C boiling water
    kcal
    (c) 0.6 kg of 100°C boiling water to 0.6 kg l00°C steam
    kcal
    (d) 0.6 kg of 0°C ice to 0.6 kg 100°C steam
    kcal
    Hello,

    you only have to use all the given constants:

    (a): 600\ g \cdot 80\ \frac{cal}{g}=48000\ cal=48\ kcal

    (b): 600 \ g \cdot 1 \ \frac{cal}{g \cdot ^\circ C} \cdot 100^\circ C=60000\ cal=60\ kcal

    (c): 600\ g \cdot 540\ \frac{cal}{g}=324000\ cal=324\ kcal

    (d); Add the results (a)+(b)+(c)

    A personal question: I'm used to measure the difference of temperatures in Kelvin and if I remember correctly the unit cal or kcal is not allowed since 1979
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