Karim occasionally cycles the 24km journey to school. When he hurries and increases his normal average speed, v, by 6km/h his journey time is cut by 40 minutes. How long does it normally take him to cycle to school?
Follow Math Help Forum on Facebook and Google+
rt=24 He increases his speed by 6, (r+6) He decreases his time by 2/3 hours, t-2/3 (r+6)(t-2/3)=24 But r=24/t ((24/t)+6)(t-2/3)=24 Solve for t.
How do I expand it? (6 + (24/t))(t - (2/3)) = 24 I tried using foil and got the stage: 6t + 20 .... = 24 The .... represents -(2/3) * (24/t). How do I do that?
Originally Posted by Jehan How do I expand it? (6 + (24/t))(t - (2/3)) = 24 I tried using foil and got the stage: 6t + 20 .... = 24 The .... represents -(2/3) * (24/t). How do I do that? Perhaps coding it will make things a bit clearer: Can you see how to do this step now, and can you continue? -Dan
View Tag Cloud