angular velocity

**rcmango** · November 22nd 2007, 01:05 PM

Two people start at the same place and walk around a circular lake in opposite directions. One has an angular speed of 1.10 10-3 rad/s, while the other has an angular speed of 3.50 10-3 rad/s. How long will it be before they meet?

answer in seconds.

how can i find the chng in time if the angular velocity is not given?

for example i have two angular speeds?

angular velocity = (angular speed1 - angular speed 2) / chng in time

**Soroban** · November 22nd 2007, 01:53 PM

Hello, rcmango!

Two people start at the same place and walk around a circular lake in opposite directions.
One has an angular speed of $1.10\times 10^{-3}$ rad/sec,
while the other has an angular speed of $3.50 \times 10^{-3}$ rad/sec.
How long will it be before they meet?

They have a combined speed of: $(1.10 \times 10^{-3}) + (3.50 \times 10^{-3}) \;=\;4.60 \times 10^{-3}$ radians/second.

How long will it take them to cover $2\pi$ radians?

$(4.60 \times 10^{-3})\,T \;=\;2\pi\quad\Rightarrow\quad T \;=\;\frac{2\pi}{4.6} \times10^3 \;=\;1365.909849$ seconds

. . Therefore: . $T \;\approx\;22\text{ min, }46\text{ sec}$

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