can some one please help with the equation of motion, I have attached the question. its confusing me cause there are two springs attached to one mass,

what I get is

$\displaystyle m \frac{d^{2}x}{dt^{2}} = -k_{1}(x-x_{0}) + k_{2} (l-x_{0}) $

but than when I solve for the equilibrium position I get

$\displaystyle x = \frac{k_{1}-k_{2})x_{0} + k_{2}l}{k_{1}} $

but the correct answer is

$\displaystyle x = \frac{k_{1}-k_{2})x_{0} + k_{2}l}{k_{1} + k_{2}} $

I dont understand how it is $\displaystyle k_{1} + k_{2} $

so my this equation $\displaystyle -k_{1}(x-x_{0}) + k_{2} (l-x_{0}) = 0 $ must be wrong

can anyone suggest how to get the correct equation for the equilibrium position?

thanks