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Math Help - Help Needed Please. Beam Calculations

  1. #1
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    Help Needed Please. Beam Calculations

    Please see attached sheet for the help required.

    I have an answer of 15KN and the length as 2.667. Please can anyone help and show workings out so I can use it as a check,

    Many Thanks.
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  2. #2
    MHF Contributor ebaines's Avatar
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    Re: Help Needed Please. Beam Calculations

    Yes, those answers are correct. Start with  \normalsiize \sum F_y = 0 to find  R_A. Then use  \normalsize \sum T_A = 0 to solve for d.
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  3. #3
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    Re: Help Needed Please. Beam Calculations

    Thank you for the quick response,

    However, I am unsure of what your mean by Fy and Ta.

    Please could you expand on this in more detail to help me understand how you worked this out.

    Thanks
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  4. #4
    MHF Contributor ebaines's Avatar
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    Re: Help Needed Please. Beam Calculations

    For the beam to be in equilibrium the sum of all forces acting in the vertical direction (or the y-direction in an x-y coordinate system) must equal 0. So:

     \sum F_y = 0 = R_A + R_B - 10KN - 15KN - 30KN

    You know that R_B = 40KN, so you can solve for R_A.

    Also to be in equilibrium the sum of moments (torques) about any point must equal 0. If you take sum of moments about support A you get:

     \sum T_A = 0 =  10KN(0.5m) -15KN(1m) + R_B(1.5m) -30KN(d-1)

    Again, given that R_B = 40KN, you can now solve for d.
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