Please see attached sheet for the help required.
I have an answer of 15KN and the length as 2.667. Please can anyone help and show workings out so I can use it as a check,
For the beam to be in equilibrium the sum of all forces acting in the vertical direction (or the y-direction in an x-y coordinate system) must equal 0. So:
You know that R_B = 40KN, so you can solve for R_A.
Also to be in equilibrium the sum of moments (torques) about any point must equal 0. If you take sum of moments about support A you get:
Again, given that R_B = 40KN, you can now solve for d.