Hi, I am having some trouble with this question.
The index of refraction of light passing from air to water is 1.33. If the angle of incidence is 38 deg, find the angle of refraction.
^ I do not quite get Snell's law =( Can you possibly explain a bit of the steps to me.
What I know is that the formula is like this:
sin theta 1 / sin theta 2 = v1 / v2
v1 / v2 = index of refraction
we are given the angle of incidence which the value of v1 .
so it would be
sin 38 deg / sin theta 2 = 1.33 ?_?
I have always thought snells law was:
n1 sin theta1=n2 sin theta2
where n1 is the refractive index of the first substance,
theta1 is the angle of incidence,
n2 is the refractive index of the second substance and
theta2 is the angle of refraction
Therefore, n1=1.00 (absolute refractive index of air)
n2=1.33 (absolute refractive index of water)
so n1 sin theta 1=n2 sin theta 2
1 sin 38=1.33sin theta2
Hope that helps