Results 1 to 3 of 3

Math Help - Linear Momentum

  1. #1
    Senior Member
    Joined
    Jan 2007
    Posts
    477

    Linear Momentum

    The lead female character in the movie Diamonds Are Forever is standing at the edge of an offshore oil rig.

    As she fires a gun, she is driven back over the edge and into the sea.

    Suppose the mass of a bullet is 0.005 kg, and its velocity is +719 m/s.

    Her mass (including the gun) is 48 kg.


    (a) What recoil velocity does she acquire in response to a single shot from a stationary position, assuming that no external force keeps her in place?
    in m/s

    (b) Under the same assumption, what would be her recoil velocity if, instead, she shoots a blank cartridge that ejects a mass of 5.0 10-4 kg at a velocity of +719 m/s?
    in m/s

    i believe it may be necessary for me to find the forces first, and use an equation involved with the principle of Linear Momementum?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,939
    Thanks
    338
    Awards
    1
    Quote Originally Posted by rcmango View Post
    The lead female character in the movie Diamonds Are Forever is standing at the edge of an offshore oil rig.

    As she fires a gun, she is driven back over the edge and into the sea.

    Suppose the mass of a bullet is 0.005 kg, and its velocity is +719 m/s.

    Her mass (including the gun) is 48 kg.


    (a) What recoil velocity does she acquire in response to a single shot from a stationary position, assuming that no external force keeps her in place?
    in m/s

    (b) Under the same assumption, what would be her recoil velocity if, instead, she shoots a blank cartridge that ejects a mass of 5.0 10-4 kg at a velocity of +719 m/s?
    in m/s

    i believe it may be necessary for me to find the forces first, and use an equation involved with the principle of Linear Momementum?
    Give this one another "shot" ( ) after you have looked at my response to the "skater" post. If you still have a question on this one after that, I'll walk you through this. (Though if you don't log on tonight, you may have to wait until Friday to get a response from me.)

    -Dan
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Senior Member
    Joined
    Jan 2007
    Posts
    477
    okay, I believe its a conservation of momentum theorem.

    such that vf2 = (-m1 * vf1) / m2

    which was -0.005 kg * 719 m/s then divided by 48 kg. which gave me -.074 m/s


    ======================
    and the second with the new mass, is -7.5 x 10^-3


    thanks.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. conservation of linear momentum
    Posted in the Math Topics Forum
    Replies: 2
    Last Post: June 29th 2009, 05:03 AM
  2. Momentum
    Posted in the Math Topics Forum
    Replies: 2
    Last Post: May 19th 2009, 10:59 PM
  3. [SOLVED] Conservation of linear momentum
    Posted in the Advanced Applied Math Forum
    Replies: 6
    Last Post: July 3rd 2008, 10:22 PM
  4. Momentum
    Posted in the Advanced Applied Math Forum
    Replies: 3
    Last Post: April 8th 2008, 02:38 AM
  5. Momentum
    Posted in the Math Topics Forum
    Replies: 3
    Last Post: October 27th 2007, 02:50 PM

Search Tags


/mathhelpforum @mathhelpforum