5+3 = 28

9+1 = 810

8+6 = 214

5+4 = 19

What is the next number If we add 7+3?

They it is 710. How can this be?

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- Feb 7th 2014, 12:34 PMnycmathWhat is the Next Number: 7+3 = ?
5+3 = 28

9+1 = 810

8+6 = 214

5+4 = 19

What is the next number If we add 7+3?

They it is 710. How can this be? - Feb 7th 2014, 01:14 PMSlipEternalRe: What is the Next Number: 7+3 = ?
Look for a pattern. In normal arithmetic, 5+3=8, which is the last digit of the number given by this "new addition". 9+1=10, which are the last two digits of the "new addition". 8+6=14, which again are the last two digits of the number they give. Finally, 5+4=9. So, each number they yield ends with the normal arithmetic. So, now you just need a pattern to find the first digit. 5-3 = 2, 9-1 = 8, 8-6 = 2, and 5-4 = 1. Hence, 7+3 could give 4 as the first digit (as 7-3 = 4 in normal addition). Then, it can be followed by 10, as 7+3=10. I would think 7+3 = 410. But, there are an infinite number of patterns. This is just one such pattern. I am sure there is a valid reason for 7+3 = 710.

- Feb 7th 2014, 04:26 PMnycmathRe: What is the Next Number: 7+3 = ?
Yes, the answer is 410.

- Feb 7th 2014, 04:32 PMsakonpure6Re: What is the Next Number: 7+3 = ?
Off topic question: Even if this is an arithmetic pattern, 5+3 != 28. So how are we able to wright 5+3 = 28 and "get away" with it?

- Feb 8th 2014, 04:57 AMSlipEternalRe: What is the Next Number: 7+3 = ?
- Feb 8th 2014, 05:43 AMnycmathRe: What is the Next Number: 7+3 = ?
It took me hours to play with this question.

I needed to combine A - B with A+B to get the final answer...so...

5 + 3 = (5-3) = 2, (5+3) = 8....28

9 + 1 = (9-1) = 8, (9+1) = 10...810

8 + 6 = (8 - 6) = 2, (8 + 6) = 14...214

etc....so...

7 + 3 = (7 - 3) = 4, (7 + 3) = 10...410

The answer is 410. - Feb 8th 2014, 06:27 AMSlipEternalRe: What is the Next Number: 7+3 = ?
Note that this binary operator is not associative or commutative. (2+1)+1 = 13+1 = 1214 while 2+(1+1) = 2+2 = 4 (hence not associative) and 5+3=28 while 3+5=-28 (hence not commutative). However, it should always be the case that a + b = +/- (b + a) with a + b = b + a if and only if $\displaystyle a=b$ (I did not verify this, it just seems likely the case).

Usually, binary operators that are not associative or commutative are of relatively little practical use.