Results 1 to 4 of 4

Math Help - function

  1. #1
    Member
    Joined
    Apr 2013
    From
    Mahinog
    Posts
    82
    Thanks
    5

    function

    The polynomial P(x) =x4-4x3+hx2-6x+2 has a factor in the form (x-m)2, find the values of m and h.

    P(x) =x4-4x3+hx2-6x+2
    P(m) = 0
    m4-4m3+hm2-6m+2=0
    P(x) =4x3-12x2+2hx-6
    P(m)=4m3-12m2+2hm-6=0
    -m5+4m4+6m2-2m=-2m5+6m4+3m2
    m5-2m4+3m2-2m=0
    m, m4-2m3+3m-2=0
    Try m=1, (1)4-2(1)3+3(1)-2=0
    Hence, m=1, h=7

    I think there is something wrong in my solution, can anyone help?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Sep 2012
    From
    Australia
    Posts
    3,612
    Thanks
    591

    Re: function

    Hey Trefoil2727.

    You should try dividing P(x) by (x-m)^2 and note that your remainder must be 0. Once you have done this you will end up with a quadratic which you can find the roots for using the standard result.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Apr 2005
    Posts
    15,536
    Thanks
    1391

    Re: function

    No, Trefoil2727, your answer, m= 1, h= 7, is exactly correct as you can see by modifying chiro's suggestion and dividing x^4- 4x^3+ 7x- 6x+ 2 by (x- 1)^2.
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Member
    Joined
    Apr 2013
    From
    Mahinog
    Posts
    82
    Thanks
    5

    Re: function

    but if I use chiro's suggestion, i would've 3 unknown(h, m and x) and i can't eliminate them..
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 2
    Last Post: March 16th 2013, 12:38 AM
  2. Replies: 20
    Last Post: November 27th 2012, 05:28 AM
  3. Replies: 0
    Last Post: October 19th 2011, 04:49 AM
  4. Replies: 4
    Last Post: October 27th 2010, 05:41 AM
  5. Replies: 3
    Last Post: September 14th 2010, 02:46 PM

Search Tags


/mathhelpforum @mathhelpforum