Graphs of velocity versus time are shown below for a car and a motorcycle travelling along the same road. The car passes the stationary motorcycle at t = 0.
What is the average acceleration (in km/h/s) of the motorcycle during the first 15 seconds?
a = Δv/Δt = 100/15 = 6.67 m/s2 = 24km/h/s
At what time does the motorcycle overtake the car?
I figured that the point at which their distances are equal is when the motorcycle overtakes the car, and as such did (using the average acceleration above):
d(motorcycle) = 3.33t2
d(car) = vt = 22.22t
3.33t2 = 22.22t
t = 6.7 seconds