
Force on rope
hi all,
Taru and Reiko simultaneously grab a 1.61 kg piece of rope and begin tugging on it in opposite directions. If Taru pulls with a force of 18.0 N and the rope accelerates away from her at 1.24 m/s2, with what force is Reiko pulling? Round your answer to 2 decimal places.
My thoughts,
force=mass*acc = 1.61 * 1.24 = 1.9964N
But the force in the other direction has to be counteracted so
Rieko must be pulling with a force of 18+1.9964 = 19.9964N => 20.00N
Is this correct?
Thanks.

Re: Force on rope
yep
maybe a better way to look at it is that the difference between the two forces causes the acceleration.
(Fr  Ft)*1.61 = 1.24 where Fr is the force Reiku is applying, and Ft is the force Taru is applying.
To be really careful you'd go ahead and associate all these forces and accelerations with vectors and just use the vector form of F=ma.