- A block is projected up an inclined plane that makes an angle θ to the horizontal. It returnsto its initial position with half its initial speed. What is the coefficient of kinetic frictionbetween the block and the plane in terms of the angle of the incline?
So i obtained coefficient of kinetic friction, u=(5/3)tan(theta). Is this correct? If not can you guide me in the right direction?
I used the kinetic energy-work theorem. That is, K(final) - K (initial)=W=F(net)(x(f)-x(i)).
And I used the theorem to describe motion on the way up and on the way down, and after simply solved the equations for the coefficient of k.friction.
I was wondering how you obtained 3/5tan(theta)? I keep obtaining 5/3tan(theta)??
In stages. For the motion of the block as a whole is to be propelled up the plane with a speed v_0 to a distance d along the plane and back down to its original point, where now has half the speed it originally did. So over the whole trip we have
(We can neglect the gravitational PE since we are starting and ending at the same point.)
The non-conservative work is due to friction for which the frictional force is always directed opposite the direction of motion. So the friction force does of work, where d is the maximum distance up the plane, measured along the plane.
Combining this we have
We need a value for d. I did this as a Newton's 2nd Law problem. Skipping the details I get that
and the acceleration of the block up the incline
down the plane and it is a constant.
Putting this together with a simple kinematics problem I get that
The energy equation now reads:
After a fair amount of simplifying I get
Which, after the cross multiplication:
I might have done this the hard way. I have a rather bad habit of doing that.
My approach may be a bit simpler:
Since final velocity is 1/2 inital velocity the KE at the end is 1/4 the KE at the beginning. The loss of 3/4 of the initial KE is due to work performed by friction as the block travels up the ramp and back down again:
where d = length of the ramp.
When the block reaches its max eleveration its PE plus work done by friction = initial KE:
Combining the two equations: