A farmer has 10 tons of watermelons stored in a barn. The

watermelons contain 99% water, by weight. During storage, the

melons dry out so that their water content is decreased to 98% of their

new weight.

What is the weight of the watermelons now?

Printable View

- Sep 30th 2013, 05:19 PMSuperMaruKidWatermelons
A farmer has 10 tons of watermelons stored in a barn. The

watermelons contain 99% water, by weight. During storage, the

melons dry out so that their water content is decreased to 98% of their

new weight.

What is the weight of the watermelons now? - Sep 30th 2013, 07:31 PMHallsofIvyRe: Watermelons
This is pretty much just arithmetic. There are 10 tons of watermelons and the are 99% water. That means they are (10)(.99)= 9.9 tons water, 0.1 tons "non-water". The melons "dry out", losing only water so that their water weight is 98% of their new weight. Let the weight of water lost, in tons, be "w". Then their total weight is 10- w and their water weight is 9.9- w. That is a ratio of . Solve for w. The new weight of the water melons is 10- w tons.

- Sep 30th 2013, 10:00 PMvotanRe: Watermelons
- Oct 1st 2013, 06:44 AMHallsofIvyRe: Watermelons
- Oct 1st 2013, 07:03 AMSorobanRe: Watermelons
Hello, SuperMaruKid!

Quote:

A farmer has 10 tons of watermelons stored in a barn.

The watermelons contain 99% water, by weight.

During storage, the melons dry out, so that their water content

is decreased to 98% of their new weight.

What is the weight of the watermelons now?

Originally, the watermelons are 99% water and 1% solids.

The farmer has 20,000 pounds of watermelons

The amount of solids is:

When the melons are reduced to pounds, they will be 2% solid.

. .

The amount of solids remains constant: .

Therefore: .