Originally Posted by

**ebaines** Not quite right. What you've calculated is the number of ways to combine 3 wins and 2 losses, which is C(5,2) = 10. But the series does not necessarily last 5 games -for example the team could sweep the first three games. Your method also doesn't take into account the fact that the last game of the series must be a win.

If you write out all possible winning combinations you have:

3 game series (no losses): WWW

4 game series (one loss): LWWW, WLWW, WWLW

5 game series (2 losses): LLWWW, LWLWW, LWWLW, WLLWW, WLWLW, WWLLW

So the total number if ways to win is 10. This happens to be the same answer you got for the case of a best-3-of-5 series, but gives a different answer than what you got for the best-4-of-7 series.