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Hey lavacelava. What have you tried? Hint: Try expanding out in terms of factorial expressions so that you get an expression in terms of n.
I've done only this
nC3 = n!/[3!*(n-3)!] (n-1)C3 = (n-1)!/[3!*(n-4)!] nC3/(n-1)C3 = (n!/[n-1]!) * (n-4)!/(n-3)! Hint: n! = n*(n-1)! = n*(n-1)*(n-2)! = n*(n-1)*(n-2)*(n-3)! = n*(n-1)*(n-2)*(n-3)*(n-4)!
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