Thread: Substitution method

Find the points of intersection between the following equations for straight lines using the substitution method.

y=x+5 and 5x-y=-1

&

y=x-3 and 2x-y=7
thx

Originally Posted by Mr Rayon

Find the points of intersection between the following equations for straight lines using the substitution method.

y=x+5 and 5x-y=-1

&

y=x-3 and 2x-y=7
thx

EQ1:
You know that y=x+5, so substitute "x+5" in for y in the other equation

5x-y=-1
5x-(x+5)=-1
5x-x-5=-1
4x-5=-1
4x=4
x=1

Now just substitute "1" in for x in either equation

5x-y=-1
5(1)-y=-1
5-y=-1
-y=-6
y=6

Now you try for the second equation.

Is this right?

y=x-3
2x-y=7
2x-(x-3)=7
2x-x+3=7
x+3=7
-3 -3
x=4
y=4-3
y=1

So x=4 and y=1 (4,1)

Originally Posted by Mr Rayon

Is this right?

y=x-3
2x-y=7
2x-(x-3)=7
2x-x+3=7
x+3=7
-3 -3
x=4
y=4-3
y=1

So x=4 and y=1 (4,1)

Yep, you got it!

-Dan

oh i understand now