4 ÷ sin(90º + φ) = 10 ÷ sin(150º – φ) equation 1 tanφ = 4 ÷ √3 equation 2 can anyone tell me how equation 1 is solved to get equation 2
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Start with the identity sin(A+B) = sinAcosB+cosAsinB. See if that helps you to make progress.
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