4 ÷ sin(90º + φ) = 10 ÷ sin(150º – φ) equation 1

tanφ = 4 ÷ √3 equation 2

can anyone tell me how equation 1 is solved to get equation 2

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- May 11th 2013, 10:41 AMabdulrehmanshahexam on monday need help (trignomentary problem)
4 ÷ sin(90º + φ) = 10 ÷ sin(150º – φ) equation 1

tanφ = 4 ÷ √3 equation 2

can anyone tell me how equation 1 is solved to get equation 2 - May 11th 2013, 11:19 AMgrillageRe: exam on monday need help (trignomentary problem)
Start with the identity sin(A+B) = sinAcosB+cosAsinB. See if that helps you to make progress.