1. ## Vector..again

The angle between vectors a and b is 45. If |a| =5 units and |b| =4 units, find the value of |a-b| and of |a+b|

2. ## Re: Vector..again

Originally Posted by Trefoil2727
The angle between vectors a and b is 45. If |a| =5 units and |b| =4 units, find the value of |a-b| and of |a+b|
Think of $\displaystyle \vec{a}~\&~\vec{b}$ as adjacent sides of a parallelogram.
Then $\displaystyle \vec{a}-\vec{b}$ is the diagonal opposite the angle between them.
$\displaystyle \vec{a}+\vec{b}$ is the diagonal opposite the angle adjacent to the angle between them.

Now use the law of cosines.

3. ## Re: Vector..again

I hope that you know that $\displaystyle |a- b|^2= |a|^2- 2a\cdot b+ |b|^2$ and $\displaystyle |a+ b|^2= |a|^2+ 2a\cdot b+ |b|^2$.

And you should know that $\displaystyle a\cdot b= |a||b|cos(\theta)$ where $\displaystyle \theta$ is the angle between a and b.

I see Plato got in just ahead of me. Different points of view about the same thing.

4. ## Re: Vector..again

but why a.b=|a||b|cos θ?

5. ## Re: Vector..again

Originally Posted by Trefoil2727
but why a.b=|a||b|cos θ?
If you have to ask, then you are in no way ready to do this question.
Why then were you asked to work this question?

6. ## Re: Vector..again

still can't find a+b..

7. ## Re: Vector..again

I don't know, maybe my teacher likes to make his students suffer

8. ## Re: Vector..again

hah, got it! thanks!