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Math Help - Fencing Anyone???

  1. #1
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    Fencing Anyone???

    A farmer wants to enclose an area of 1500 square metres. Suppose that along the road adjoining his property he would like to use a more expensive fence, and that no fence is needed along one side of the area perpendicular to the road as it is bounded by a river.

    Ive made an image to represent this below. Excuse my crude use of paint!.....


    my questions are... explain why Y = 1500/X? ,

    and how do I show that the quantity to be minimised is
    C = 40X + 22500/X ?


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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by bobchiba View Post
    A farmer wants to enclose an area of 1500 square metres. Suppose that along the road adjoining his property he would like to use a more expensive fence, and that no fence is needed along one side of the area perpendicular to the road as it is bounded by a river.

    Ive made an image to represent this below. Excuse my crude use of paint!.....


    my questions are... explain why Y = 1500/X? ,
    the area enclosed by the fence is the area of the rectangle with sides x and y. so A = xy = 1500, since they told us the area is 1500. solving for y gives you y = 1500/x

    and how do I show that the quantity to be minimised is
    C = 40X + 22500/X ?
    more information is needed here. you haven't told us the cost of the fence or anything
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