A satellite is in a circular orbit about the earth (ME = 5.98 x 10^24 kg). The period of the satellite is 4.80 x 10^4 s. What is the speed at which the satellite travels?
should be in m/s
not sure about what the equation is and how to reach the speed.
where m is the mass of the satellite, M is the mass of the Earth, and r is the distance from the center of mass of the satellite to the center of mass of the Earth. (r is not simply the height above the ground.)
where T is the period. (Note that this is true only for circular motion.)
Inserting this equation into our "GM" equation:
<-- Note: We could have started from here using one of Kepler's Laws. (The 2nd?)
Up until now, this is identical to hummeth's solution.
Now recall the GM equation:
We can simplify this a bit, but as the result gives nothing of value, you can simply calculate it from here. I get that v = 3737.56 m/s.
I would say the force involved is the centripetal force of weight pushing toward the earth.
however, i received the answer as: 3740 m/s.
I'm still not sure how this answer was reached.
other than some formulas like Fc = (m * v^2) / r
and then: sqrt( (G * Me) / r )
and then for then T = period,
so, v = (2 * pi * r) / T
i still could not reach the correct answer because variables were missing like r
still need help with this one.
Equations "pulled out of the hat" can be dangerous. Use your powers wisely.