A skier slides horizontally along the snow for a distance of 27 m before coming to rest. The coefficient of kinetic friction between the skier and the snow is ľk = 0.050 Initially, how fast was the skier going?
not sure how to reach the answer with so few variables involved.
equations i thought i might use were: vf = sqrt((2 * (KE) / m)
and KE = 1/2*(m * v^2)
thanks for any extra help.
Since the friction force is in the opposite direction to the displacement we have
So what's the normal force? Again we solve this using a Free-Body Diagram. In this case the answer is simple: , thus
Now, the skier starts with a speed . At the end, the skier is at rest, so v = 0 m/s. Thus
So finally we have:
which you can solve for .