# Maths problem

• Nov 1st 2007, 06:31 AM
Maths problem
I have been given a maths problem which I cannot do, I need help, the problem is as follows, ' you have an integer number and you move the first digit to the back the new number increases by 50%, what is the original number?'

For example if you started with the number 23456 and moved the first digit to the back the new number would be 34562 or 23490 the new number would be 34902. Help!!!!!!
• Nov 1st 2007, 06:41 AM
kalagota
Quote:

I have been given a maths problem which I cannot do, I need help, the problem is as follows, ' you have an integer number and you move the first digit to the back the new number increases by 50%, what is the original number?'

For example if you started with the number 23456 and moved the first digit to the back the new number would be 34562 or 23490 the new number would be 34902. Help!!!!!!

is the answer unique? didn't they give you how many digits the integer has?
• Nov 1st 2007, 09:08 AM
I’m not sure if the answer is unique and it could be any number of digits so if you write it out you get the following equation:

3/2(A x 10^n + b x 10^n-1 + c x 10^n-2……. ) = B x 10^n + c x 10^n-1 + d x 10^ n-2......

From this you get the following (which I think is correct):

3/2 A = b, 3/2b = c, 3/2c= d ……

Therefore:

3/2a = b, (3/2)^(2) a = c, (3/2)^(3) a = c …….

I get stuck from there lol