centripetal acceleration of car

**rcmango** · Oct 31st 2007, 09:06 PM

A car travels at a constant speed around a circular track whose radius is 2.6 km. The car goes once around the track in 330 s. What is the magnitude of the centripetal acceleration of the car?
and i get 9.4E-4 m/s^2

and that seems to be the wrong answer.

first i used: (2 * pi * r) / T

and then
i used: a = v^2 / 2 for centripetal acceleration

please help me with this one.

**CaptainBlack** · Nov 1st 2007, 12:40 AM

Originally Posted by rcmango

A car travels at a constant speed around a circular track whose radius is 2.6 km. The car goes once around the track in 330 s. What is the magnitude of the centripetal acceleration of the car?
and i get 9.4E-4 m/s^2

and that seems to be the wrong answer.

first i used: (2 * pi * r) / T

and then
i used: a = v^2 / 2 for centripetal acceleration

please help me with this one.

$a=v \dot\theta=\frac{2\pi~r}{t}~\frac{2\pi}{t}=\frac{4 \pi^2~r}{t^2}=\frac{4\pi^2~2600}{330^2}\approx 0.94 ~\rm{ m/s^2}$

where

Thread: centripetal acceleration of car

LinkBack

Thread Tools

Display

centripetal acceleration of car

Similar Math Help Forum Discussions

Deriving Centripetal Acceleration?

Physics- centripetal and tangential acceleration

from (centripetal) acceleration a(x,y) to x(t) and y(t)

tangential and centripetal acceleration explanation

linear speed and centripetal acceleration

Search Tags