It's an ice CUBE.
just a little rusty on the conversion side of maths at the moment, so was wondering about this question:
'An ice cube is 2.00 in. on a side and weighs 1.2*10^2 grams.
a) what is the density of the ice?
b) what volume of water (d=1.00g/ml) is obtained when the ice cube melts?'
I have attempted part a, but never got the real answer (which is 0.916g/cm^3)
so here is what I was starting:
d=mass/vol.
mass = 1.20*10^2g
converting in. to cm: 1in. = 2.54cm
therefore 2in. * (2.54cm/1in.) = 5.08 cm.
therefore vol.= pi(5.08)^2(5.08)
= 411.85
so d=mass/vol.
1.20*10^2g/411.85=0.291
I don't know what I have messed up, but if someone could help me understand, that would be appreciated!!
The only thing that you did wrongly was the calculation of the volume of the cube.
Suppose that you have a rectangular box, picture a shoe box say.
If its dimensions are a cm * b cm * c cm, what is its volume ?
For a cube, a = b = c.