1. ## If C++ statements

Hi I have worked on a question where you input 3 positive number and the program gives you the middle of those so if i put in 1,2,3 it will give me 2. Here is the code but it is not complete. I do not know what I am missing because if I put the numbers : 9,6,7 or 4,2,3 it does not out put the correct number. Also if you think there is a better way of writing this code, please tell me!

Code:
//Challenge 4#include <iostream>
using namespace std;
int main () {

int x;
int y;
int z;

int counter=0;
int m=0;

cout<<"Please input the weight of all three bowls:  ";
cin>>x;
cin>>y;
cin>>z;

if(x>y&&y>z)
m=y;
if(x>y&&y<z)
m=z;
if(x>z&&y>z)
m=y;
if(x>z&&y<z)
m=z;
if(y>x&&x<z)
m=z;
if(y>x&&x>z)
m=x;
if(y>z&&z>x)
m=z;
if(y>z&&z<x)
m=x;
if(z>y&&y>x)
m=y;
if(z>y&&y<x)
m=x;
if(z>x&&y>x)
m=y;
if(z>x&&y<x)
m=x;
//does not work for 967 or 423 ....?? why?

cout<<m<<endl;

return 0;

}

2. ## Re: If C++ statements

Uhm, there are just $\displaystyle 3!=6$ cases:

x > y > z
x > z > y
y > x > z
y > z > x
z > x > y
z > y > x

Code:
#include<iostream>
using namespace std;
main ()
{
int x, y, z, m;
cout<<"Please input the weight of all three bowls: \n";
cin>>x>>y>>z;

if (x>y && y>z)
m=y;
if (x>z && z>y)
m=z;
if (y>x && x>z)
m=x;
if (y>z && z>x)
m=z;
if (z>x && x>y)
m=x;
if (z>y && y>x)
m=y;

cout<<m;
}
For your code and x = 9, y = 6, z = 7:

Code:
if(x>y&&y>z)
m=y;
if(x>y&&y<z)
m=z; //m=7
if(x>z&&y>z)
m=y;
if(x>z&&y<z)
m=z;
if(y>x&&x<z)
m=z;
if(y>x&&x>z)
m=x;
if(y>z&&z>x)
m=z;
if(y>z&&z<x)
m=x;
if(z>y&&y>x)
m=y;
if(z>y&&y<x)
m=x; //m=9
if(z>x&&y>x)
m=y;
if(z>x&&y<x)
m=x;

thank you!