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Math Help - Stuck on Ideal Gas Law

  1. #1
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    Stuck on Ideal Gas Law

    A weather balloon carries instruments that
    measure temperature, pressure, and humidity as
    it rises through the atmosphere. Suppose such a
    balloon has a volume of 1.2 m 3 at sea level where
    the pressure is 1 atm and the temperature is
    20 C. When the balloon is at an altitude of 11 km
    (36,000 ft) the pressure is down to 0.5 atm and the
    temperature is about − 55 C.
    What is the volume of the balloon then?
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  2. #2
    Super Member sakonpure6's Avatar
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    Re: Stuck on Ideal Gas Law

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  3. #3
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    Re: Stuck on Ideal Gas Law

    That looks like a homework question, in that case hope this site helps:

    online tutoring at tutorsville.net
    Last edited by TheRedWizard; February 28th 2013 at 03:44 AM.
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  4. #4
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    Re: Stuck on Ideal Gas Law

    Ideal gas law: PV= NRT. where "P" is the pressure, "V" is the volume, "N" is the number of molecules, "R" is a constant, and "T" is the temperature in degrees Kelvin. 20 degrees C is about 20+ 274= 294 degrees K and -55 C is about -55+ 274= 219 degrees K.

    You are told that "such a balloon has a volume of 1.2 m 3 at sea level where the pressure is 1 atm and the temperature is 20 C."
    So (1)(1.2)= (NR)(294).

    You are also told that "When the balloon is at an altitude of 11 km (36,000 ft) the pressure is down to 0.5 atm and the temperature is about − 55 C." and asked to find the volume.
    So (0.5)V= (NR)(219).

    Divide that equation by the first: \frac{(0.5)V}{(1)(1.2)}= \frac{(NR)(219)}{(NR)(294)}
    which reduces to \frac{V}{2.4}= \frac{219}{294}.
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    Re: Stuck on Ideal Gas Law

    Nice.It is very helpful post for me.
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    Re: Stuck on Ideal Gas Law

    Unexpected ending in doctor season 1 stimulates me to buy more Video.
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