hey, I'm having a huge problem trying to figure out this problem. It is using probability and counting principles.
The problem is:
Hamburger hut sells regular hamburgers as well as a larger burger. Either type can include cheese, relish, lettuce, tomato, mustard, or catsup.
A.) How many different hamburgers can be ordered with exactly 3 extras?
B.) how many different regular hamburgers can be ordered with exactly three extras?
C.) How many different regular hamburgers can be ordered with at least five extras?
If anyone can help me solve/figure out how to pull apart this problem it would be much appreciated! very stuck right now
You titled this "counting principle" so apparently you know what that is. There are two choices for "regular" or "larger hambuger. There are six "extras" so you have 6 choices for the first, 5 choices for the second, and 4 choices for the third. How many is that altogether, using the "counting principle"?
  |
LinkBack URL
About LinkBacks