# physics particles problem

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• Oct 25th 2007, 07:36 PM
rcmango
physics particles problem
three particles far away from any other objects and located on a straight line.
The masses of these particles are:
mA = 363 kg,
mB = 517 kg, and
mC = 154 kg.

Find the magnitude and direction of the net gravitational force acting on each of the three particles (let the direction to the right be positive).

what is particle A in Newtons
what is particle B in Newtons
what is particle C in Newtons

what is going on with this problem? Please help.

heres a pic of whats going on: http://img81.imageshack.us/img81/3663/p498in0.gif
• Oct 26th 2007, 01:29 AM
Spimon
The force of attraction between 2 particles in space is given by Newton's Theory of Gravitation (see first image).

Each particle has the right to view itself as stationary and the other particles moving towards it, so the arrows in the final diagram don't necessarily represent the direction of movement. This just shows the force between the 2 particles (may not be relevant depending on what level of study you are at). And of course as the direction to the right is defined as positive, to the left is negative (which I forgot to add in the diagrams).
http://img508.imageshack.us/img508/1192/gravco8.jpg

http://img171.imageshack.us/img171/7...ractionqk0.jpg
• Oct 27th 2007, 10:37 AM
rcmango
okay, i see how particle A has the answer of 5.67 x 10^-5,

however, it seems that your finding the magnitude of A to C and then adding A to B with it. If its the magnitude of A to C we want, why add an extra A to B with it.

I'm just confused of whats going on really. but i see how the answers were calculated.

thanks alot.