How do you calculate it is? is it

Velocity inst. = (df - di)/(tf - ti)

or what??

and instantaneous velocity is the average velocity between two points right?

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- February 16th 2013, 03:15 PMsakonpure6Instantaneous Velocity!
How do you calculate it is? is it

Velocity inst. = (df - di)/(tf - ti)

or what??

and instantaneous velocity is the average velocity between two points right? - February 16th 2013, 03:34 PMILikeSerenaRe: Instantaneous Velocity!
Not quite.

Average velocity = (d_{f}- d_{i})/(t_{f}- t_{i})

Instantaneous velocity is the velocity at one point.

It is what you get if pick your t_{i}and t_{f}at the same time.

You can't really do that since you'd be dividing by zero, but you can make the one approach the other as close as you want.

This is what you do when you calculate a limit. - February 16th 2013, 03:44 PMsakonpure6Re: Instantaneous Velocity!
- February 16th 2013, 03:47 PMILikeSerenaRe: Instantaneous Velocity!
- February 16th 2013, 03:55 PMsakonpure6Re: Instantaneous Velocity!
well i have a set of data that makes up an increasing exponential function and i am supposed to find the acceleration of it and to do that my teacher said to take the instantaneous velocity between all two data points which would give me a linear function of where i can determine the acceleration by finding the slope.

So i have the first two data points (0s , 0 cm [E]) and ( 0.05s, 0.80 cm [E]) , i determined that the instantaneous velocity between those points is 16 cm/s [E] at 0.025s. Is that right? - February 16th 2013, 03:57 PMILikeSerenaRe: Instantaneous Velocity!
What sort of set of data are you talking about?

- February 16th 2013, 04:02 PMILikeSerenaRe: Instantaneous Velocity!
I think I understand.

You have a set of data with a number of consecutive times, probably separated by 0.05 seconds.

At each time you have a distance traveled in centimeters.

Indeed, in that case the approximation of the instantaneous velocity is the average velocity between 2 consecutive points.

This works because those 2 points are close enough together. - February 16th 2013, 04:14 PMsakonpure6Re: Instantaneous Velocity!
so my answer of 16 is right?

- February 16th 2013, 04:15 PMILikeSerenaRe: Instantaneous Velocity!
- February 16th 2013, 04:16 PMsakonpure6Re: Instantaneous Velocity!
oh great! thank you very much!!!!!!!!!!!!!!!!