Attachment 26931its the part b that i need help in . well i tried to solve it but failed to do so i arrived to equation v= V-u but cant go any furthur as after i plug this in v^2 things get quite complicated

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- Feb 9th 2013, 10:36 PMabdulrehmanshaha physics questions really teasing me
Attachment 26931its the part b that i need help in . well i tried to solve it but failed to do so i arrived to equation v= V-u but cant go any furthur as after i plug this in v^2 things get quite complicated

- Feb 9th 2013, 11:33 PMa tutorRe: a physics questions really teasing me
So did you get the equations right in part a? I'll assume you did.

Rearranging them a little gives:

$\displaystyle u-v=\frac{M}{m}V$

and

$\displaystyle u^2-v^2=\frac{M}{m}V^2$

Factorise the left side of the second equation and everything will become easy. - Feb 10th 2013, 09:22 PMabdulrehmanshahRe: a physics questions really teasing me
i didnt actually get it can u please elaborate it a little thanks

- Feb 11th 2013, 12:02 AMa tutorRe: a physics questions really teasing me
$\displaystyle a^2-b^2=(a+b)(a-b)$

- Feb 11th 2013, 12:26 AMabdulrehmanshahRe: a physics questions really teasing me
this is how i solve can u point out at what am i doing wrong

v=V-u equation 2

mv+MV=mu equation 1

multiplying eq 2 by M

we get Mv=MV+Mu equation 3

adding equation 3 and 1 we get

v=(m-M)u/(m+M) equation 4

multiplying eq 2 by m

mv=mV-mu equation 5

adding equation 5 and 1 we get

V=2mu/(m+M)

plugging these values in the energy loss in kinectic energy

mu^2{1-(m+M)2-4mM/(m+M)^2 i get 0/(m+M)^2 i know i am close but what i am doing wrong?? - Feb 11th 2013, 09:29 PMabdulrehmanshahRe: a physics questions really teasing me
can anoyne please help please i got exam tom