Area of a trapezium

**dravid2** · Oct 25th 2007, 02:30 AM

How do you work out the area of a trapezium.

An example would be good as well.

Thanks in advance

**Spimon** · Oct 25th 2007, 08:08 AM

The formula is 1/2 (a+b) * h

Example:
Area = 1/2*(5+8)*3
= 1/2*(13)*3
= 19.5 units squared

**Sean12345** · Oct 25th 2007, 08:13 AM

Let a and b be the parallel sides of the trapezium.
Let h be the height of the trapezium.

$A=\frac{h(a+b)}{2}$

Example: A trapezium of height 6cm has 2 parallel sides one is 10cm the other is 8cm. Find the area of the trapezium.

Using the formula:

$A=\frac{h(a+b)}{2}$

$A=\frac{6(10+8)}{2}$

$\implies A=\frac{6(18)}{2}$

$\implies A=\frac{108}{2}$

$\implies A=54cm^2$

**dravid2** · Oct 25th 2007, 09:07 AM

thx a lot m8, that was loadz of help

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