How do you work out the area of a trapezium.
An example would be good as well.
Thanks in advance
Let a and b be the parallel sides of the trapezium.
Let h be the height of the trapezium.
$\displaystyle A=\frac{h(a+b)}{2}$
Example: A trapezium of height 6cm has 2 parallel sides one is 10cm the other is 8cm. Find the area of the trapezium.
Using the formula:
$\displaystyle A=\frac{h(a+b)}{2}$
$\displaystyle A=\frac{6(10+8)}{2}$
$\displaystyle \implies A=\frac{6(18)}{2}$
$\displaystyle \implies A=\frac{108}{2}$
$\displaystyle \implies A=54cm^2$