Consider the reaction between phosphorous and hydrogen to produce phosphine.
P4 + 6H2 -> 4PH3
0.2 mol of phosphorous and 0.8 mol of hydrogen are placed in an empty 1L vessel. The vessel is sealed and allowed to equilibrate. At equilibrium, 0.2 mol of PH3 are present. Write the equilibrium expression for the reaction and determine the equilibrium constant.
For the equilibrium constant I wrote Kc = Reactants/products = (PH3^4)/(P4)(H2^6)
After finding the equilibrium concentrations for the reactants, my answer is 0.68. I need to know if this is right?
Would the answer be different if it wasn't a 1L vessel? If it was a 2L vessel?