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  1. #1
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    Physics and math

    Hi guys. Iv got a real fun one for you today. Its actually a physics question but its solved using math equations (substitution or elimination)

    A skier on a slope inclined at 4.7 degrees to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7 m/s. The coefficient of kinetic friction between skis and snow is 0.11. Determine how far the skier will slide before coming to a rest.

    We can consttruct a triangle with that and figure out FG parallel(Pa) and FG perpendicular(Pe). so

    \frac {sin90}{9.81m} = \frac {sin4.7}{FgPa}
    Im not sure what to construct my other equation from. Id appreciate help. Thanks guys
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  2. #2
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    Quote Originally Posted by ffezz View Post
    Hi guys. Iv got a real fun one for you today. Its actually a physics question but its solved using math equations (substitution or elimination)

    A skier on a slope inclined at 4.7 degrees to the horizontal pushes on ski poles and starts down the slope. The initial speed is 2.7 m/s. The coefficient of kinetic friction between skis and snow is 0.11. Determine how far the skier will slide before coming to a rest.

    We can consttruct a triangle with that and figure out FG parallel(Pa) and FG perpendicular(Pe). so

    \frac {sin90}{9.81m} = \frac {sin4.7}{FgPa}
    Im not sure what to construct my other equation from. Id appreciate help. Thanks guys
    I would use the work-energy theorem.

    W_{nc} = \Delta E = \Delta PE + \Delta KE

    The only nonconservative force here is the frictional force, so
    -f_k x = (mgh - mgh_0) + \left ( \frac{1}{2}mv^2 - \frac{1}{2}mv_0^2 \right )

    So define a zero point for your gravitational potential energy and find your normal force. The skier stops when v = 0 m/s. (You will also need to find your h's in terms of the slope length x and the angle the slope makes with the horizontal.)

    -Dan
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