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Math Help - Calculate the volume of acid.

  1. #1
    Senior Member sakonpure6's Avatar
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    Calculate the volume of acid.

    2Al + 6HNO3 -------> 2Al(NO3)3 + 3H2

    What volume of 2.40M acid ( HNO3) is required to have a complete reaction with the mass of Al ( 39.1g & that is about 1.45 mol ).

    Here is what I did but I am not sure if it is right

    # mol acid/ 1.45 mol Al = 6 mol acid/ 2 mol Al

    #mol acid = 1.8125

    now if that's right, what do i do next to find the volume?

    Thank you in advance!
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  2. #2
    MHF Contributor

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    Re: Calculate the volume of acid.

    Yes, you need 6/2= 3 times as many mols of acid as of aluminum. Since you have 1.45 mols of aluminum, you will need 3(1.44)= 4.35 mols of acid. Now by "2.40M acid", I presume you mean one mol of acid per liter (it's been a while since I took chemistry!) so you would need \frac{4.35}{2.40}= 1.8125 liters of acid. That is volume, not number of mols.
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  3. #3
    Senior Member sakonpure6's Avatar
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    Re: Calculate the volume of acid.

    oh great thank you!
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