Attachment 26571people i tried to understand as to how my friend solved this question but to avail can anyone help me understand as to how he solved it how he got that angle 97.1
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Attachment 26571people i tried to understand as to how my friend solved this question but to avail can anyone help me understand as to how he solved it how he got that angle 97.1
What your friend was trying to do was to add the 250 N force to the x and y forces by components. That is to say if we break the 250 N force into x and y components we getQuote:
Originally Posted by abdulrehmanshah
In the x direction: 160 N + 250*0.96 = 400 N
In the y direction: 370 N - 250*0.28 = 300 N
Unfortunately he/she didn't add them correctly and got the wrong components.
To finish the problem from here we are looking for a vector R such that x + y + R = 0. (Note carefully what direction R is in!)
As far as the angle 97.1, the angle the 250 N force is pointed in is acs(0.96) = 16.26 degrees below the x axis. So that number is wrong. (That may be why he/she got the components wrong.)
-Dan
Attachment 26577 A=tan^-1(160/370) B=90-16.26=73.74 . A+B=97.1. see that vector of magnitude came by resolving two vectors in X axis and Y axis finding their resultant which is 403 i hope u understand. i was able to solve by the method u did in the first place but this second method really confused me now it is fun
