Help me out these easy geometry problems.?

**I want the explanation too, cause i don't understand the question properly and then put it clearly, cause i am just 8th class student. best of answers will be given 5 *'s, plus a thumbs up.**

1.In ▲ PQR, PD ┴ QR and PO is the bisector of ∠ QPR. If ∠ PQR = 65° and ∠ PQR = 23.5°,then

∠ DPO in degrees=

2.In a parallelogram PQRS,the bisectors of ∠ P and ∠ Q meet on RS.If the perimeter PQRS is 13.5 cm, then the measure of QR =

3.A circle is passing through three vertices of a rhombus of side 8cm and its centre is the forth vertex of the rhombus. Find the length of the longest diagonal of the rhombus.

4.In a rhombus ABCD, the diagonals intersect each other at O.If ∠ A = 60° and OA = 2 cm, then the side of the rhombus is =

5.In a rhombus PQRS,the diagonals intersect at O.Given that, ∠ P = 120° and OP = 3 cm. What is the side of the rhombus is =

6.P is an interior point of quadrilateral ABCD and B = 3.5 cm,BC = 4 cm,CD = 4.8 cm and AD = 3.7 cm.Then the possible value of ( AP+BP+CP+DP) =

7. MN and PS are 2 equal chords of a circle drawn on the either side of centre O of the circle. Both the chords are produced to meet at point A.If the radius of the circle is 10 cm, MN = 12 cm and OA= 17 cm, then NA =

8. In ▲ ABC , if ∠ A < ∠ B < 45°, then ▲ ABC is a/an .................................... triangle.

9. If G is the centroid of ▲ ABC, then the area of ▲ BGC is ............................... thimes the area of the quadrilateral ABCG.

If you can pr**ovide a diagram also, it is good.... but if you can't it's not even a silly problem.. Please answer this question.I am trying for many Days ( nearly about 4 days.) Help me out.. ♣♣**(Bow)

Re: Help me out these easy geometry problems.?

Hello, kohila!

Here is some help . . .

Quote:

3. A circle is passing through three vertices of a rhombus of side 8cm

and its centre is the forth vertex of the rhombus.

Find the length of the longest diagonal of the rhombus.

We have rhombus .

The center of the circle is

Since , the rhombus

. . is made of two equilateral triangles.

Hence:

Code:

` B`

*

8 * : * 8

* : *

* : *

A * * * * * * * * * C

* : *

* : *

8 * : * 8

*

O

Law of Cosines: .

. . . . . . . . . . . .

Therefore: .

Quote:

4. In a rhombus ABCD, the diagonals intersect each other at O.

If ∠ A = 60° and OA = 2 cm, find the length of a side of the rhombus.

Once again, the rhombus is comprised of two equilateral triangles.

Code:

` B`

*

* : *

* : *

* 2 : *

A * - - - + - - - * C

* :O *

* : *

8 * : * 8

*

D

The altitude of the equilateral triangle is 2.

Code:

` *`

*|*

* | * x

* |2 *

* | *

* | *

* * * * * * *

x/2

Pythagorus: .

. . . . . . . . .

. . . . . . . . . .

Re: Help me out these easy geometry problems.?

thank you.. you can answer all but y u delayed.