# need help on sequences topic

• Dec 25th 2012, 03:52 AM
abdulrehmanshah
need help on sequences topic
Find and simplify an expression for the sum of the natural numbers from (n + 1) to 2n inclusive.
i tried to solve it but couldnt i came to 0.5*(3n+1)(n-1) ...this is the answer according to my book (3/2)n^2 + n/2. could someone hint me towards getting this answer
• Dec 25th 2012, 04:23 AM
Plato
Re: need help on sequences topic
Quote:

Originally Posted by abdulrehmanshah
Find and simplify an expression for the sum of the natural numbers from (n + 1) to 2n inclusive. according to my book (3/2)n^2 + n/2.

$\sum\limits_{k = n + 1}^{2n} k = \sum\limits_{k = 1}^{2n} k - \sum\limits_{k = 1}^n k$
• Dec 25th 2012, 04:27 AM
MarkFL
Re: need help on sequences topic
edit: pipped at the post! (Giggle)
• Dec 25th 2012, 05:13 AM
ibdutt
Re: need help on sequences topic
It is an AP with the first term = ( n+1), common difference 1 and last term = 2n
Also from n+1 to 2n we have n terms.
Using expression for sum of n terms of an AP we get S = n/2 [ 2a + ( n-1) d )
Thus we have (n+1) + ( n+2) + (n+3) + ..... + 2n = n/2 [ 2(n+1) + ( n-1) x 1 ] = n/2 [ 2n + 2 + n - 1 ] = n/2[ 3n + 1 ] = (3/2 ) n^2 + (n/2)
• Dec 25th 2012, 05:29 AM
Plato
Re: need help on sequences topic
Quote:

Originally Posted by ibdutt
It is an AP with the first term = ( n+1), common difference 1 and last term = 2n
Also from n+1 to 2n we have n terms.
Using expression for sum of n terms of an AP we get S = n/2 [ 2a + ( n-1) d )

In order to do these problems you should know the so-called Gauss Sum:
$\sum\limits_{k = 1}^M k = \frac{{M\left( {M + 1} \right)}}{2}$.

So according to that we get $\frac{{2n(2n + 1)}}{2} - \frac{{n(n + 1)}}{2}$.