Can someone please help me with this question

Use the inductive property:

nC(r+1) = (n-r)/(r+1) * nCr

to prove the Pascal triangle property that nCr + nC(r+1) = (n+1)C(r+1)

This is how I started..

nCr + (n-r)/(r+1) * nCr = (n+1-r)/(r+1) * nCr -->

nCr (1+ (n-r)/(r+1)) = nCr (n+1-r)/(r+1)

I don't know what to do next..