Find x:
x = sq.root[1 + sq.root( 1 + sq.root(1 + sq.root(1 +....
"The dots mean that the series go till infinity.
By attempt the answer should be (1 +-sq.root(5))/2 but that is not the answer.
Hello, Aditya3003!
By attempt the answer should be: , but that is not the answer.
Since is obviously positive,
. . you must reject the negative root:
While solving, you squared the equation, right?
. . This can introduce an extraneous root.