Find x:

x = sq.root[1 + sq.root( 1 + sq.root(1 + sq.root(1 +....

"The dots mean that the series go till infinity.

By attempt the answer should be (1 +-sq.root(5))/2 but that is not the answer.(Headbang)

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- Dec 21st 2012, 11:52 PMAditya3003Root problem
Find x:

x = sq.root[1 + sq.root( 1 + sq.root(1 + sq.root(1 +....

"The dots mean that the series go till infinity.

By attempt the answer should be (1 +-sq.root(5))/2 but that is not the answer.(Headbang) - Dec 22nd 2012, 12:03 AMjakncokeRe: Root problem
/the answer is

The infinite nested radicals, = golden ratio.

Since golden ratio says then so solving - Dec 22nd 2012, 12:08 AMibduttRe: Root problem
Could you please write as to what is the answer given. The answer you have got appears to be correct.

Attachment 26322 - Dec 22nd 2012, 12:10 AMjakncokeRe: Root problem
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- Dec 22nd 2012, 06:06 AMSorobanRe: Root problem
Hello, Aditya3003!

Quote:

By attempt the answer should be: , but that is not the answer.

Since is obviously positive,

. . you must reject the negative root:

While solving, youthe equation, right?*squared*

. . This can introduce an extraneous root.