Thread: Chemistry Dilution problem! Please Help!

You have determined that the concentration of HCL is 0.870ml/L. How would you prepare 2.00L of the solution from a stock solution of HCL with a concentration of 11.8 ml/L?

Please help me!

Originally Posted by sakonpure6

You have determined that the concentration of HCL is 0.870ml/L. How would you prepare 2.00L of the solution from a stock solution of HCL with a concentration of 11.8 ml/L?

Please help me!

2*0.87 mol /l = mols HCL required
2*0.87 = xliter*11.8

x=0.147 liter

Originally Posted by bjhopper

2*0.87 mol /l = mols HCL required
2*0.87 = xliter*11.8

x=0.147 liter

thank you i just solved it by myself too!